[wplug] Bash conditional help

[Moshe Hyzon]

In the interest of "There's more than ONE way to do it!"....



case "$myvar" in
  *apple*)
    echo "We've got an apple!"
    ;;
  *)
    echo "No apple here."
    ;;
esac


Moshe Hyzon


On Fri, May 2, 2008 at 2:34 PM, David J. Pryke <david-wplug at pryke.us> wrote:
>
> scoob8000 wrote:
>  > I'm having a little brain fart here..
>  >
>  > How can I use an if then else to test for partial matches in a variable?
>  >
>  > For example, say I want to match on "apple" below...
>  >
>  > myvar=orange orange apple grape
>  >
>  > if [ "$myvar" = "apple" ]; then
>  > echo Variable contains apple
>  > else
>  > echo Variable does not contain apple
>  > fi
>  >
>  > Thanks
>
>  Use double square brackets and a double-equals test with wildcards.
>
>  For example, this script:
>  ==========================================
>  #!/bin/bash
>
>  if [ 1 == 1 ]
>  then
>          echo "1=1"
>  fi
>
>  if [[ "1" == "1" ]]
>  then
>          echo "1=1 with quotes"
>  fi
>
>  if [[ "123456" == *34* ]]
>  then
>          echo "123456 contains 34"
>  fi
>
>  if [[ "123456" == *d4* ]]
>  then
>          echo "123456 contains d4"
>  fi
>  ============================================
>
>  will output:
>  =====================
>  1=1
>  1=1 with quotes
>  123456 contains 34
>  =====================
>
>
>  Full reference for this behavior is here:
>  http://tldp.org/LDP/abs/html/comparison-ops.html
>
>  --
>  Thanks,
>
>  David J. Pryke
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