[wplug] Bash conditional help

[David J. Pryke]

scoob8000 wrote:
> I'm having a little brain fart here.. 
> 
> How can I use an if then else to test for partial matches in a variable?
> 
> For example, say I want to match on "apple" below...
> 
> myvar=orange orange apple grape
> 
> if [ "$myvar" = "apple" ]; then
> echo Variable contains apple
> else
> echo Variable does not contain apple
> fi
> 
> Thanks

Use double square brackets and a double-equals test with wildcards.

For example, this script:
==========================================
#!/bin/bash

if [ 1 == 1 ]
then
         echo "1=1"
fi

if [[ "1" == "1" ]]
then
         echo "1=1 with quotes"
fi

if [[ "123456" == *34* ]]
then
         echo "123456 contains 34"
fi

if [[ "123456" == *d4* ]]
then
         echo "123456 contains d4"
fi
============================================

will output:
=====================
1=1
1=1 with quotes
123456 contains 34
=====================


Full reference for this behavior is here:
http://tldp.org/LDP/abs/html/comparison-ops.html

-- 
Thanks,

David J. Pryke