[wplug] about basic programming

[Arnaud Loos]

The program would print out "Counting 39 up" then the num++ would increment
num to 40. Your while loop would then evaluate the statement (40 < 40) which
is false and therefore it would exit. If you had (num <= lastnum) then it
would print out "Counting 40 up".

Arnaud- 

-----Original Message-----
From: wplug-bounces+arnaud=arnaudloos.com at wplug.org
[mailto:wplug-bounces+arnaud=arnaudloos.com at wplug.org] On Behalf Of Tom
Rhodes
Sent: Friday, March 04, 2005 3:52 PM
To: General user list
Subject: Re: [wplug] about basic programming

On Fri, 4 Mar 2005 14:03:13 -0500
John Harrold <jmh17 at pitt.edu> wrote:

> Sometime in March Juan Zuluaga assaulted the keyboard and produced:
> 

[SNIP]: Discussion on books.

Perhaps someone with years of experiance in programming could tell me
something.  In the following program snip-it:

#include <stdio.h>

#define lastnum 40

int main()
{

  int num = 0;

  while ((num == 0) || (num < lastnum))
    {
      printf("Counting %d up\n", num);
      num++;
    }
  return 0;
}

num is only incremented to 39, one below 40.  Thus far I have always
considered it was because we stop at the number before the one we define.
So I have always wrote as such.  Yet, I have not found an explination in
either of my two C books.
Am I missing or not properly enterpreting a paragraph/sentence in my books?

Yea, I'm sure everyone thinks I'm nuts now since I should know this, but,
eh, whatever.  *hand in the air* You don't know me!
:)

--
Tom Rhodes
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