[wplug] cross scripting question

[Poyner, Brandon]

It can be done...

$ uname 
Linux 
$ date
Wed Aug  3 08:29:21 EDT 2005
$ date --date="-1 day" +%Y-%m-%d
2005-08-02

Brandon Poyner
Network Engineer III
CCAC - College Office
412-237-3086
 
 

> -----Original Message-----
> From: wplug-bounces+bpoyner=ccac.edu at wplug.org 
> [mailto:wplug-bounces+bpoyner=ccac.edu at wplug.org] On Behalf 
> Of Tom Rhodes
> Sent: Tuesday, August 02, 2005 9:44 PM
> To: wplug at wplug.org
> Subject: [wplug] cross scripting question
> 
> Hi,
> 
> I'm working on a backup script to be implemented in Solaris,
> Linux, and FreeBSD environments.  Now I have some problems with
> the version of Linux date(1).  It doesn't seem to comply with
> POSIX and requires a completely different format then that of
> ISO 8601.  Basically, what I need is a way to output the date
> subtract one day.  Is there an easy way to do this on Linux?
> 
> I need to print the date in the following format:
> 
> 2005-08-02
> 
> But I want to subtract one day from that (so that the filename
> is one day before the check).
> 
> Any help would be great ... otherwise, guess I could use some
> awk(1) and sed(1) magic here.  :(
> 
> -- 
> Tom Rhodes
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